Remove Duplicates from Sorted List II
Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list.
Example
Given 1->2->3->3->4->4->5, return 1->2->5.
Given 1->1->1->2->3, return 2->3.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 | /** * Definition for ListNode * public class ListNode { * int val; * ListNode next; * ListNode(int x) { * val = x; * next = null; * } * } */ public class Solution { /** * @param ListNode head is the head of the linked list * @return: ListNode head of the linked list */ public static ListNode deleteDuplicates(ListNode head) { // write your code here ListNode dummy = new ListNode(0); dummy.next = head; head = dummy; while (head.next != null && head.next.next != null) { if (head.next.val == head.next.next.val) { int val = head.next.val; while (head.next != null && head.next.val == val) { head.next = head.next.next; } } else { head = head.next; } } return dummy.next; } } |