Given two non-empty binary trees s and t, check whether tree t has exactly the same structure and node values with a subtree of s. A subtree of s is a tree consists of a node in s and all of this node's descendants. The tree s could also be considered as a subtree of itself.
Example 1:
Given tree s:
Given tree s:
3 / \ 4 5 / \ 1 2Given tree t:
4 / \ 1 2Return true, because t has the same structure and node values with a subtree of s.
Example 2:
Given tree s:
Given tree s:
3 / \ 4 5 / \ 1 2 / 0Given tree t:
4 / \ 1 2Return false.
Solution:
If t is a subtree of s, it starts at some node in t and will be identical from that node.
Therefore, from t, we try going left and going right to find the node that is identical to s.
Code:
/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ public class Solution { public boolean isSubtree(TreeNode s, TreeNode t) { if (s == null) { return false; } if (isSametree(s, t)) { return true; } return isSubtree(s.left, t) || isSubtree(s.right, t); } public boolean isSametree(TreeNode s, TreeNode t) { if (s == null && t == null) { return true; } if (s == null || t == null) { return false; } return s.val == t.val && isSametree(s.left, t.left) && isSametree(s.right, t.right); } }