Given two strings s and t, determine if they are isomorphic.
Two strings are isomorphic if the characters in s can be replaced to get t.
All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.
For example,
Given
Given
"egg"
, "add"
, return true.
Given
"foo"
, "bar"
, return false.
Given
"paper"
, "title"
, return true.
Note:
You may assume both s and t have the same length.
You may assume both s and t have the same length.
Solution:
This problem is a simplified version of Word Pattern.
Code:
public class Solution { public boolean isIsomorphic(String s, String t) { if (s.length() != t.length()) { return false; } HashMap<Character, Character> map = new HashMap<>(); for (int i = 0; i < s.length(); i++) { char c1 = s.charAt(i); char c2 = t.charAt(i); if (!map.containsKey(c1)) { map.put(c1, c2); } else { if (map.get(c1) != c2) { return false; } } } map.clear(); for (int i = 0; i < t.length(); i++) { char c1 = t.charAt(i); char c2 = s.charAt(i); if (!map.containsKey(c1)) { map.put(c1, c2); } else { if (map.get(c1) != c2) { return false; } } } return true; } }