Given a binary array, find the maximum length of a contiguous subarray with equal number of 0 and 1.
Example 1:
Input: [0,1] Output: 2 Explanation: [0, 1] is the longest contiguous subarray with equal number of 0 and 1.
Example 2:
Input: [0,1,0] Output: 2 Explanation: [0, 1] (or [1, 0]) is a longest contiguous subarray with equal number of 0 and 1.
Note: The length of the given binary array will not exceed 50,000.
Solution:
1. Replace all 0s to -1s in the array.
2. Problem becomes find maximum size subarray sum equals 0. (Maximum Size Subarray Sum Equals k)
Code:
public class Solution { public int findMaxLength(int[] nums) { for (int i = 0; i < nums.length; i++) { if (nums[i] == 0) { nums[i] = -1; } } HashMap<Integer, Integer> map = new HashMap<>(); map.put(0, -1); int sum = 0; int max = 0; for (int i = 0; i < nums.length; i++) { sum += nums[i]; if (map.containsKey(sum)) { max = Math.max(max, i - map.get(sum)); } else { map.put(sum, i); } } return max; } }